Question

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(3) In random experiment two balls selected at random out of 3 red and 4 green balls.
Fill the boxes to find the probability of getting one red and one green ball.​

Answer 1

Answer:

The odds of drawing a green on first try is ( 7/16 ) . After that the number of balls in the bag is 16–1 = 15 balls. From those 15 balls, 5 are red therefore the probability of drawing a red is ( 5/15 ). Now, the probability of these two events happening together is (5/15) x (7/16) = 7/48.

Answer 2

Step-by-step explanation:

❤HEY DUDE HERE IS UR ANSWER❤

the total probablitity of selecting 2 boys out of 7 is done in 7c2 ways....

according to the question the probability of getting one red is 3c1 ×and one green ball is 4c1...

therefore probability is 3c1×4c1 divided by 7c2

the final answer that you get is:12/21

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