Question

3. In square triangle BCD, E is a point on CD such that
BEC = 60°. Find angle DBE.​

Answer 1

Answer:

Step-by-step explanation:

As it is a square ,each angle measures 90°

So,in triangle BEC

ANGLE BCE+ANGLE CEB+ANGLE CBE=180°. (ASPT)

90°+60°+angle CBE=180°

150°+ANGLE CBE=180°

ANGLE CBE=180-150

=30°

ANGLE BEC + ANGLE BED is equal to 180 degree. (Linear pair)

60 degree + angle b e d is equal to 180 degree

Angle BED is equal to 180 - 60 degree

= 120°

As diagonal of the square bisect angle 90 degree to 45 degree each

Angle BDE=45°

IN TRIANGLE B E D

ANGLE DBE+ ANGLE BED+ ANGLE EDB=180°. (ASPT)

ANGLE DBE+ 120°+45°=180°

ANGLE DBE+165°=180°

ANGLE DBE=180-165

=15°

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