Question

3) In the adjoining figure , if two parallel eine
AB and CD are cut by a transversal Ef at G
and H and angle 1 and angle 2are
in the ratio
3:2
then find angle 5 and angle

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Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

First we need to find angle 1 and 2.

• We are given the ratio as 3:2
• And also they are Linear Pair
• This means that the sum equals 180 degree
• Angle 1 is 3x and angle 2 is 2x.

$3x+2x=180 ^\circ$

$5x = 180 ^ \circ$

$\boxed{x = 36 ^ \circ}$

Now, angle 1 is 108 degree.

And, angle 2 is 72 degree.

• Angle 2 and angle 4 is Vertically Opposite angles
• Angle 4 and Angle 6 are alternate Interior angles
• Hence angle 6 is 72 degree
• Angle 2 = Angle 4 = Angle 6 = 72 degree.

• Angle 1 and angle 3 are in Vertically Opposite angles
• Angle 3 and angle 5 are Alternate Interior angles
• And so  , Angle 5 = 108 degree.
• Angle 1 = Angle 3 = Angle 5.

Answer 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

ANSWER:-

• First we need to find angle 1 and 2.

• We are given the ratio as 3:2
• And also they are Linear Pair
• This means that the sum equals 180 degree

Angle 1 is 3x and angle 2 is 2x.

3x+2x=180 ^\circ3x+2x=180 °

5x = 180°

x=36°

Now, angle 1 is 108 degree.

And, angle 2 is 72 degree.

• Angle 2 and angle 4 is Vertically Opposite angles
• Angle 4 and Angle 6 are alternate Interior angles
• Hence angle 6 is 72 degree
• Angle 2 = Angle 4 = Angle 6 = 72 degree.
• Angle 1 and angle 3 are in Vertically Opposite angles
• Angle 3 and angle 5 are Alternate Interior angles
• And so , Angle 5 = 108 degree.
• Angle 1 = Angle 3 = Angle 5.

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