Math, asked by maxsteve1107, 9 months ago

3. In the figure, ABDC is a quadrant of a circle of radius 14 cm and a semi-circle is drawn with diameter BC. Find the area of the shaded region.

Answers

Answered by aymanuzayr05
0

Answer:

FIRST SHOW THE FIGURE

Step-by-step explanation:

Answered by inpu1akshu
3

Answer:

Step-by-step explanation:

Area of the quadrant ABCD

= 1/4πr^2

=1/4×22/7×14×14

=154cm^2

Area of the semicircle

=1/2πR^2

= 1/2× 22/7× 7×7

=77cm^2

Area of total shaded region=area of quadrant ABCD+ area of semicircle

=> 154+77

= 231 cm^2

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