3. In the figure, ABDC is a quadrant of a circle of radius 14 cm and a semi-circle is drawn with diameter BC. Find the area of the shaded region.
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0
Answer:
FIRST SHOW THE FIGURE
Step-by-step explanation:
Answered by
3
Answer:
Step-by-step explanation:
Area of the quadrant ABCD
= 1/4πr^2
=1/4×22/7×14×14
=154cm^2
Area of the semicircle
=1/2πR^2
= 1/2× 22/7× 7×7
=77cm^2
Area of total shaded region=area of quadrant ABCD+ area of semicircle
=> 154+77
= 231 cm^2
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