Question

3 In the figure AD = BC and AD // BC. Prove that triangleADC = triangleCBA.​

Answer 1

Step-by-step explanation:

in triangle ADC and triangle BBC

AC= AC ( common )

AD= BC ( given )

angle C = angle A ( alternate interior angle )

therefore by SAS congruence these triangles are equal...

Answer 2

Answer:

BY THE CRITERION OF SSA ∆ADC & ABC∆.

Step-by-step explanation:

IN ∆ADC & ABC∆

1)AC = AC (COMMON TO BOTH ∆'s)

2)AD = BC(GIVEN)

3) angle CAB = angle ACD (alt. int. angle)

THEREFORE

∆ADC ≈ ∆ABC (by SSA) (both ∆are only congurent ∆ADC = ∆ABC (CPCT)

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