3. In the figure find the value of PTQ
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hi. l. am. dêépãk rãj ãryã
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OPT=∠OQT=90
o
(Tangents of circle)
So ∠POQ+90
o
+90
o
+50
o
=360
o
∠POQ=360
o
−230
o
∠POQ=130
o
.
Answer:
thanks
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