Question

3. In the figure, ir PQ | RS, then
(a) aº+bº=cº
(b) aº+ bº= 180º
(c) aº+bº -cº =180º
(d) dº + 8° = 90° + c​

Answer 1

∠GEF=180−∠CEF(∵∠GEF and ∠CEF are complementary angles)

∴∠GEF=30°

and ∠GCD=∠GEF (from the figure, CD∣∣EF)

⇒∠GCD=30°

Now, ∠BCD=∠BCG+∠GCD

⇒∠BCD=25°

+30 °

=55°

∠ABC=∠BCD(∵AB∣∣CD)

∠ABC=x=55°

Therefore the value of x is 55.