Question

3.
In the figure theta = tan-(under root 2), then the correct direction of the magnetic field at P can be shown by the arrow​

Answer 1

θ = tan⁻¹$\sqrt{2}$, then the correct direction of the magnetic field

For M.cosθ pt P is at axis, so direction of magnetic field will be along M.cosθ and for M.sinθ pt P is perpendicular

So, direction will be just opposite to M Sinθ

Bₐ = (μ₀/ 4π) × (2M cosθ)/r³

B₁ = (μ₀/ 4π) × (2M sinθ)/r³

tanα = B₁/Bₐ = (tanθ)/2

Given that θ = tan⁻¹$\sqrt{2}$

or tanθ = $\sqrt{2}$

tanα = $\frac{\sqrt{2} }{2}$ =  $\frac{1}{2}$

tanα = 1/ tanθ

tanα = cotθ

tanα = tan(π/2 - θ)

θ = (π/2 - θ)

or θ + θ = π/2

so, Direction will be shown by 1

Know More

Q.1.- Then the correct direction of the magnetic field at p can be shown by the arrow

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Q.2.- What does the arrow of the magnetic field lines indicate

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