3 in the given figure ABC is right angled at C and CD 1 AB. I _A = 50°. Find a) ACD (Ans. 40" 40" b) ABC
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hope this helps you:))))))
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we know that
angel a =50° and right angel is formed at d
so,
a +d+ c =180°
50°+90°+c= 180
140+ c =180
c= 180-140
c= 40°
sorry for late I didn't saw you rrquest
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