Question

3.
In the given figure, AD and BC are perpendicular
to line segment AB and AD=BC. If CD intersects
AB at P, show that P is the mid-point of AB as
well as that of CD.
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

In triangle ADP And BCP

AD = BC

angle A = angle B ( equal to 90 degree )

angle APD = angle BPC (vertically opposite angle)

triangle ADP is congruent to triangle BCP

AP = BP ( by c.p.c.t )

DP = CP ( by c.p.c.t )

therefore p is the midpoint of AB as well as CD