Question

3. In the given figure, angleBAC = 32°, angleBCE = 161º. Find,angle angleABC and angleDBC.
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Answer 1

Step-by-step explanation:

let the angle BCA be x°

we know that angle of a straight line is 180° so

angle BCE+angleBCA =180°

161+x°=180°

x=19° this is equation 1 (angleBCA)

let the angle ABC be y

we know that sum of angle in a triangle is 180°

angle BAC+ angle BCA+ angle ABC=180°

32°+19°+y=180°

y=180-51°

y=129° (angleABC)

we know that the angle mafe by the straight line is always 180° so

angle ABC+angleCBD=180°

129+angle CBD=180°

angleCBD=180-129

angleCBD=51°

hence (angleABC=129°)

(angleDBC=51°)