Question

3. In the
given figure, OABC is rhombus. Find
Angle AOB and Angle BOC , where 'O' is the centre of circle.​

Answer 1

Answer:

Let the r be the radius of the circle.

.:.0A = OB = OC =r .. (0

DOABC is a rombus.

.(1) ... OA = OB = AB = BC = OC =r

..OA= AB = BC = OC

From (i) and (ii) we get,

Thus,

AOAB and AOBC are equilateral triangle

having each side r meter.

Also, we know that diagonal of a parallelogram divides it into two triangles of equal areas.

Area of AOBC = Area of AOAB ... (iii)

Area of a rhombus OABC 32/3m? Area of AOAB+ Area of AOBC 32/3m2

2x Area of OAB = 32/3m?

2 x 3 r2 4 = 32/3m?

=>r2 = 64

=>r=8m

Step-by-step explanation:

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