Math, asked by dineshkumar750btd, 1 month ago

3 In the given figure, rays OA, OB, OC and OD are such that \_ AOB 56°, \_BOC = 100°, \_COD = xº and \_ DOA = 74º. Find the value - of x. ​

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Answered by premakumari391331
2

Answer:

हम वह जानते हैं,

एक बिंदु के चारों ओर सभी कोणों का योग होता है 3 6 0

हे

.

इसलिए,

1 0 0

हे

+5 6

हे

+7 4

हे

+एक्स=3 6 0

हे

एक्स=१ ३ ०

हे

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