3 In the given figure, rays OA, OB, OC and OD are such that \_ AOB 56°, \_BOC = 100°, \_COD = xº and \_ DOA = 74º. Find the value - of x.
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हम वह जानते हैं,
एक बिंदु के चारों ओर सभी कोणों का योग होता है 3 6 0
हे
.
इसलिए,
1 0 0
हे
+5 6
हे
+7 4
हे
+एक्स=3 6 0
हे
एक्स=१ ३ ०
हे
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