Question

3. In the given figure show that AB is parallel to EF. B 66 E F 36° 150 30° 0 D​

Answer 1

Answer:

Step of Construction:

Construct a line segment OA

Considering O as centre and suitable radius construct an arc cutting the line OA at the point B 

Considering B as a centre and suitable radius as before constructing an arc to cut the previous arc at the point C

Considering C as centre and same radius cut the arc at the point D

Considering C as a centre and the radius more than half of CD construct an arc 

Considering D as a centre and same radius construct another arc to cut the previous arc at the point E 

Join E so we get ∠AOE=90o

Considering B as centre and radius more than half of CBconstruct and arc

Considering C as the centre and same radius construct an arc with cuts the previous arc at the point F

Join OF 

Therefore, F is the bisector of the right ∠AOE.