Question

3.)In the given figure, two chords AB and CD of a circle intersect each other at a point E such that angle BAC = 45°, angle BED = 120°. Then find angle BDE

( please solve it step by step )

Answer 1

Hey mate!
The answer to your question is in the attachment
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Answer 2

$\huge \mathfrak \color{purple}{Answer}$

$\huge \sf \blue{ = 15°}$

Given

• O is the centre of a circle of which the chords AB and CD intersect at E.
• ∠BAC=45° and ∠BED=120°.
• To find out- ∠ABD=?

$\huge \bf \underline{solution}$

• ∠BAC=45°=∠BDC
• Since both the angles are on the same chord BC ( the angles, subtended by a chord to different points of the circumference are equal).
• So in ΔBDE, we have
• ∠EBD or ∠ABD=180°−(∠BED+∠BDE)=180°−(120°+45°)=15°.