Question

3* in the isosceles triangle ABC,
and are equal.is an exterior angle of
AABC. The measures of ZACB and ZACD are (3x – 17)° and (8x + 10) respectively.
Find the measures of
Also find the measures of ZA and ZB.​

Answer 1

Answer:

Hello !!!! <ACB+<ACD=(3x-17)+(8x+10)=180 , or 11x - 7 = 180 , or 11x = 187 , or x=17. SO<ACB=51-17=34^ , and <ACD= 136 + 10 = 146 degrees 7 = 34 degrees A=<B=(180-34)/2=146/2=73^ ACB = 34 deg, <ACD=146 c deg, <A=<B =73^ .