Question

3. In the isosceles triangle ABC, the bisectors BO and Co meet at O. Find mZBOC
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Answer 1

Answer:

Step-by-step explanation:

Given BD is Bisector of ∠ABC and CO is Bisector of ∠ACB produce CB to D

In ΔABC

AB=AC

∠ACB=∠ABC

2

1

​

∠ACB=

2

1

​

∠ABC

∠OCB=∠OBC

in ΔBOC

∠OBC+∠OCB+∠BDC=180

∘

2∠OBC+∠BOC=180

∘

∠ABC+∠BOC=180

∘

∠ABC+∠OBA=180

∘

∠DBA=∠BOC