3. In the isosceles triangle ABC, the bisectors BO and Co meet at O. Find mZBOC
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Answer:
Step-by-step explanation:
Given BD is Bisector of ∠ABC and CO is Bisector of ∠ACB produce CB to D
In ΔABC
AB=AC
∠ACB=∠ABC
2
1
∠ACB=
2
1
∠ABC
∠OCB=∠OBC
in ΔBOC
∠OBC+∠OCB+∠BDC=180
∘
2∠OBC+∠BOC=180
∘
∠ABC+∠BOC=180
∘
∠ABC+∠OBA=180
∘
∠DBA=∠BOC
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