Math, asked by dakshror6097, 6 days ago

3.
In the number A4b, A is the smallest two digit perfect cube and A's unit place digit exceeds
b by 3. Then the sum of the number and its cube root is
(2) 2754
(3) 2750
(4) 2758
A 2713​

Answers

Answered by gamerdirgh068
0

√30 because it has many ans come to it ans

Answered by Dhruv4886
11

Given:

In the number A4b, A is the smallest two-digit perfect cube and A's unit place digit exceeds  b by 3.

To Find:

Then the sum of the number and its cube root is

(1) 2713

(2) 2754

(3) 2750

(4) 2758

Solution:

It is given in the number A4b, A is the smallest two-digit perfect cube and A's unit place digit exceeds  b by 3,

So the smallest two-digit perfect cube will be 27 which is the cube of 3, so A will be,

A=27

And it is said that b is 3 less than the unit digit of A, so b will be,

b=7-3

 =4

So the number will be,

Number=2744

Now it is said to find the sum of the number and its cube root, which will be,

Sum=2744+\sqrt[3]{2744}\\=2744+\sqrt[3]{14*14*14}  \\=2744+14\\=2758

So the sum comes as 2758.

Hence, the correct option is (4).

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