Question

3. In the triangle PQR, PQ=QR, ∠PQR =400, PS is the Altitude to the sideQR, Then ∠QPS = A)40 0 B) 50 0 C) 80 0 D) 90 0

Answer 1

Answer:

angle QPS = 50 0(option B)

Step-by-step explanation:

In triangle PQS,

angle Q + angle PSQ + angle QPS = 180 0

=> 40 + 90 + Angle QPS => 180 0

=> Angle QPS = 180 - 130

=> Angle QPS = 50 0 (answer)