Question

3. In triangle, ABC, AB = AC and angle BAC = 38°. BCD is a straight line. Work out the size of angle ACD?​

Answer 1

Since AB=AC, the triangle is an isosceles triangles.

So, its base angles will be equal.

Let the two base angles be x

Now,

BAC + ABC + ACB = 180 (Angle sum property)

38 + x + x = 180

38 + 2x = 180

2x = 142

x = 71

Therefore, Angle ABC = ACB = 71°

Now,

Since BCD is a straight line,

ACB + ACD = 180 (Linear Pair)

71 + ACD = 180

ACD = 109°

Therefore, angle ACD = 109°

Please marks as Brainliest :)

Answer 2

Answer:

bac=38

NOW

ABC+BAC+CAB=180

ACB+CAB=142

HEAR AB=AC

SO

ACB & CAB =71

NOW ACD+ACB=180

ACD=109 IS ANSWER