3 In triangle ABC, D and E are points on AB and AC respectively such that DE II BC and AD: DB = 2:3 IF AE = 6cm, then find EC.
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Given AD/BD=3/1
Using Basic proportionality theorem, In a triangle a line is drawn parallel to one side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio.
In ΔABC⇒BDAD=ECAE⇒13=EC6.6⇒EC=2.2
Now AC=AE+EC
AC=6.6+2.2=8.8 cm
Using Basic proportionality theorem, In a triangle a line is drawn parallel to one side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio.
In ΔABC⇒BDAD=ECAE⇒13=EC6.6⇒EC=2.2
Now AC=AE+EC
AC=6.6+2.2=8.8 cm
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