Question

3)In triangle ABC, LBAC = 90° and ADI BC. Prove that
AC2 = BC.DC
Plz help me with this question ​

Answer 1

Answer:

In ∆ACB and ∆ADC

angle A = angle D = 90°

angle ACB= angle ACD

therefore, ∆ ACB= ∆ ADC

so , AC/ AD= CA/ BC= CD/ AB

SI, AC SQUARE= BC. DC