Question

3. In triangle ABC right angled at A if tan C = √ 3 then find the value of sin B+ cos C.​

Answer 1

Answer:

Value of

SinBCosC + cosBsinC = 1

Step-by-step explanation:

Given In ABC, <A = 90° =

ZB + ZC = 90° - (1) - -

Value of

SinBCosC + cosBsinC

Sin(B + C)

/* SinXCosY +CosXsinY =sin(X+Y) */

= Sin90°

/* From (1) */

1

Therefore,

Value of

SinBCosC + cosBsinC = 1

Hope it helps

Answer 2

Step-by-step explanation:

tan(c) = √3

tan(c) = tan 60°

c = 60°

given

a = 90°

c = 60°

then b = 30°

so, sin B + sin C

= 1/2 + 1/2

= 1

hope this helps you