Question

3 is a zero of p(x) = 3xx
ax - 45. Find 'a'.​

Answer 1

Answer:

$3 {x}^{2} + ax - 45 = 0 \\ 3 \times {3}^{2} + 3a - 45 = 0 \\ 27 + 3a - 45 = 0 \\ 3a = 18 \\ a = 6$

Answer 2

${3{x}^{2}+ax-45=0}$

${3×{3}^{2}+a×3-45=0}$

${27+3a-45=0}$

${3a-18=0}$

${3a=18}$

${a=6}$