Question

3 is added to twice a number gives 41.Then find the number?​

Answer 1

Answer -

• The number is 19.

To find -

• The number.

Step-by-step explanation :-

Let the number be "x".

Then -

• Twice the number will be "2x".

Adding 3 to it -

• We get "2x + 3".

According to the Question,

• 2x + 3 = 41.

Therefore -

$\longmapsto \bf2x + 3 = 41$

$\bf \longmapsto 2x = 41 - 3$

$\longmapsto \bf 2x = 38$

$\longmapsto \bf x = \dfrac{38}{2}$

$\longmapsto \bf x = 19$

Hence :-

• The number is 19.

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Verification -

• To check our answer, let's substitute the value of "x" in the equation and see whether LHS = RHS.

LHS :

$\implies 2x + 3$

$\implies 2 \times 19 + 3$

$\implies 38 + 3$

$\implies 41$

RHS :

$\implies 41$

LHS = RHS.

Hence verified!!

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Answer 2

Given :

• 3 is added to twice a number gives 41.

To Find :

• The number.

Solution :

Let the number be x.

ATQ,

↦ 2x + 3 = 41

↦ 2x = 41 - 3

↦ 2x = 38

↦ x = 38/2

↦ x = 19

Hence, the number is 19.

Verification :

Substituting x = 19, we get

↦ 2x + 3 = 41

↦ (2 × 19) + 3 = 41

↦ 38 + 3 = 41

↦ 41 = 41

Hence, verified. ✔️