√3 is iratinal prove
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let √3 be a rational number, then
√3=a/b (where a and b are co prime).
√3b=a. ......(í)
on squaring both side of eq. í,
we get,
3b²=a². ......(íí)
let a²=c
then,
c= 3b². .......(ííí)
From eq. í, íí and ííí we get that a and b have common factor 3 but initially we had said that a and b are co prime. So,o ur assumption was wrong and by the method of contradiction, √3 is irrational...
hope this helps ..
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