Question

3. Is it possible to design a rectangular mango grove whose length is twice its breadth,
and the area is 800 m2? If so, find its length and breadth.​

Answer 1

Step-by-step explanation:

let the length be x

and breadth be 2x

area of rectangle is L*B

A. T. Q.

2X(X) = 800

2Xsq.=800

xsq. =800/2

xsq. = 400

x = √400

x=20

now put the value of x in length and breadth

Answer 2

Let the breadth of mango grove be l.

Length of mango grove will be 2l.

Area of mango grove = (2l) (l)= 2l2

2l2 = 800

l2 = 800/2 = 400

l2 – 400 =0

Comparing the given equation with ax2 + bx + c = 0, we get

a = 1, b = 0, c = 400

As we know, Discriminant = b2 – 4ac

=> (0)2 – 4 × (1) × ( – 400) = 1600

Here, b2 – 4ac > 0

Thus, the equation will have real roots. And hence, the desired rectangular mango grove can be designed.  

l = ±20

As we know, the value of length cannot be negative.

Therefore, breadth of mango grove = 20 m

Length of mango grove = 2 × 20 = 40 m