Math, asked by singhmehakpreet2008, 3 months ago

3. Is it possible to design a rectangular mango grove whose length is twice its breadth,
and the area is 800 m²? If so, find its length and breadth.​

Answers

Answered by Anonymous
3

Answer :

  • Breadth is 20 m and length is 40m

Given :

  • Length is twice its breadth
  • Area is 800m²

To find :

  • Length
  • Breadth

Solution :

  • Let the breadth be x
  • Let the length be 2x

As we know that,

  • Area of rectangle = l × b

Where,l is length 2x and b is breadth x

⇢ Area of rectangle = length × breadth

⇢ 800 = 2x × x

⇢ 800 = 2x²

⇢ x² = 800/2

⇢ x² = 400

⇢ x = ±√400

⇢ x = ± 20

Then , x = 20 or x = - 20

  • x cannot be negative so, x = 20

Now we have to find the length and breadth:

  • Breadth = x = 20 m
  • Length = 2x = 2(20) = 40 m

Hence, Breadth is 20 m and length is 40m

More Explanation :

  • Perimeter of rectangle = 2(l + b)
  • Area of rectangle = length × breadth
  • Diagonal = √(l² + b²)
  • Where , l is length and b is breadth
Answered by Anonymous
51

A N S W E R :

\\

  • The Breadth is 20m

  • The Length is 40m

\\

Given :-

\\

  • Length is twice its breadth
  • Area is 800 m²

\\

To find :-

\\

  • Find Length ?
  • Find Breadth ?

\\

\large\underline{\frak{As ~we~ know ~that,}}

\large\dag Formula Used :

  • \boxed{\bf{Area~of~rectangle~=~Length~×~Breadth}}

\\

Solution :-

\\

  • Let the breadth be x
  • Let the length be 2x

\\

• L is the length 2x and B is the breadth x

\\

:\impliesArea of reactangle = Length × Breadth

\\

~~~~~:\implies800 = 2x × x

\\

~~~~~~~~~~:\implies800 = 2x²

\\

~~~~~~~~~~~~~~~:\impliesx² = \large{\sf{\frac{800}{2}}}

\\

~~~~~~~~~~~~~~~~~~~~:\impliesx² = {\cancel{\dfrac{800}{2}}}

\\

~~~~~~~~~~~~~~~~~~~~~~~~~:\impliesx² = 400

\\

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~:\impliesx = {\sf{±√400}}

\\

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~:\implies{\underline{\boxed{\pink{\frak{x~=~±20}}}}}

\\

\large\dashrightarrowx = 20

~~~~~\large\dashrightarrowx = -20

\\

\therefore Hence,

\\

  • x cannot be negative

  • x = \large\underline{\rm{20}}

\\

V E R I F I C A T I O N :

\\

• Find the length and breadth :

  • The Breadth = x = 20m

  • The Length = 2x = 2(40) = 40m

\\

\large\dag Hence Verified !!

\\

  • The Breadth is = \large\underline{\rm{20m}}

  • The Length is = \large\underline{\rm{40m}}
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