√3 is rational or irrational. explain
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Irrational because it can't be expressed in ratio form
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Hey there!!!
√3 is an irrational
=>> If possible , let √3 be rational and let it's simplest form be a/b.
Then , a and b are integers having no common factor other than 1, and b is not equal to 0.
Now , √3 = a/b => 3 = a² / b²
=> 3b² = a²
=> 3 divides a²
=> 3 divides a
[ 3 is prime and 3divides a² => 3 divides a ]
Let a = 3c for some integer c.
putting a = 3c in (i) , we get
3b² = 9c => b² = 3c²
=> 3 divides b² [ 3 divides 3c² ]
=> 3 divides b.
[ 3 is prime and 3 divides b² => 3 divides b]
Thus, 3 is a common factor of a and b.
but , this contradicts the fact that a and b have no common factor other than 1.
The contradiction arises by assuming that √3 is rational wrong.
Hence, It is √3 an irrational.
Hope it helped!!!☺️
√3 is an irrational
=>> If possible , let √3 be rational and let it's simplest form be a/b.
Then , a and b are integers having no common factor other than 1, and b is not equal to 0.
Now , √3 = a/b => 3 = a² / b²
=> 3b² = a²
=> 3 divides a²
=> 3 divides a
[ 3 is prime and 3divides a² => 3 divides a ]
Let a = 3c for some integer c.
putting a = 3c in (i) , we get
3b² = 9c => b² = 3c²
=> 3 divides b² [ 3 divides 3c² ]
=> 3 divides b.
[ 3 is prime and 3 divides b² => 3 divides b]
Thus, 3 is a common factor of a and b.
but , this contradicts the fact that a and b have no common factor other than 1.
The contradiction arises by assuming that √3 is rational wrong.
Hence, It is √3 an irrational.
Hope it helped!!!☺️
AliaRoy01:
hey
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