Question

-3 is the 0 of polynomial x³+ax²+11x+6 find the value of A​

Answer 1

Answer:

Here you go my friend!

Step-by-step explanation:

Since -3 is the zero of the polynomial, the value of "x" in p(x)= -3

Now:-

p(x)= x³+ax²+11x+6

p(-3)= (-3)³+a(-3)²+11(-3)+6

p(-3)= -27+9a-33+6

p(-3) = -60+6+9a

        = -54+9a

    9a= 54

       a= 54/9

      a= 6    

Therefore A or a= 6

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