Question

3 is the root of x+1/2+x-1/2=3 substituion method​

Answer 1

Let

be p and

be q

2p + 3q = 2 …III

4p – 9q = -1 …IV

Multiplying eq. III by 3 and subtracting with eq. IV, we get

6p + 9q = 6

4p – 9q = -1

10p = 5

p =

substitute value of p in Eq. III

+ 3q = 2

⇒ 3q = 2 – 1

⇒ q =

But,

⇒

⇒

⇒ x = 4

⇒

⇒

⇒ y = 9