Question

3,k-2,5 are in A.P. find k.solve fast​

Answer 1

$\huge \red{\mathfrak{solution}}$

GIVEN:

3 , K-2 and 5 are in A.P

TO FIND :

k =?

As we know that ,

For A.P

$\boxed{ \bold{t2 - t1= t3 - t2}}$

And here ,

•t1= 3

•t2=k-2

•t3=5

$\boxed{ \bold{t2 - t1= t3 - t2}}$$\rightarrow \: k - 2 - 3 = 5 - (k - 2) \\ \\ \rightarrow \: k - 5 = 5 - k + 2 \\ \\ \rightarrow \: k - 5 = 7 - k \\ \\ \rightarrow \: k + k = 7 + 5 \\ \\ \rightarrow \: 2k = 12 \\ \\ \rightarrow \: k = \cancel \frac{12}{2} 6 \\ \\ \rightarrow \: \boxed{ \green{ \bold{k = 6}}}$