Question

3^k+8=27^2k+1 find value of k?​

Answer 1

Step-by-step explanation:

3^k+8 =27^(2k+1)

3^k+8 = 3^3(2k+1)

remove 3on both sides

k+8 = 6k+3

k-6k = 3-8

-5k =-5

k =1

Answer 2

$1) \: \: \: {3}^{k + 8} = {27}^{2k + 1} \: find \: the \: value \: of \: k. \\ solution. \\ {3}^{k + 8} = {( {3}^{3}) }^{2k + 1} \\ {3}^{(k + 8)} = {( {3}) }^{3(2k + 1)} \\ k + 8 = 3(2k + 1) \\ k + 8 = 6k + 3 \\ 8 - 3 = 6k - k \\ 5 = 5k \\ \frac{5}{5} = k \\ 1 = k \\ or \: \: k = 1 \: \: is \: the \: answer... \\ hope \: its \: help \: you$