3
k
h gives k = 36, i.e., k = +6.
k - 3
k
3k = k? - 3k, i.e., 6k = k?, which means k = 0 or k = 6.
fore, the value of k, that satisfies both the conditions, is k=6. For this value, the
linear equations has infinitely many solutions.
EXERCISE 3.5
Which of the following pairs of linear equations has unique solution, no solution, or
afinitely many solutions. In case there is a unique solution, find it by using cross
ultiplication method.
(1) x-3y-3=0
3x-9y-2=0
(ii) 2x + y = 5
3x+2y=8
(iii) 3x - 5y = 20
6x-10y=40
(iv) x - 3y - 7=0
3x - 3y - 15 = 0
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