3
k
K-3
OF LIN
k
k
12
we need
3
=
12
k
ich gives k = 36, i.e., k = +6.
3 k - 3
k k
res 3k = K2 - 3k, i.e., 6k = k2, which means k = 0 or k = 6.
50,
ir of linear equations has infinitely many solutions.
EXERCISE 3.5
1. Which of the following pairs of linear equations has unique solution, no s
infinitely many solutions. In case there is a unique solution, find it by
multiplication method.
(1) x-3y-3 = 0
(i) 2x +y=5
3x-9y-2=0
3x +2y=8
(ii) 3x - 5y = 20
(iv) x-3y-7=0
6x - 10y = 40
3x - 3y - 15 = 0
2. (1) For which values of a and b does the following pair of linear equ
infinite number of solutions?
erefore, the value of k, that satisfies both the conditions, is k= 6. For this
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