Math, asked by ashmita14, 1 year ago

3. Kashyap is 21 years old and kinshuk is 15 yeasrs younger than kashyap. After how many years will kashyap be twice as old as kinshuk?

please help me to solve this question

Answers

Answered by MathManiac

Answer:

after 9 years

Step-by-step explanation:

as the difference among them remains constant, for older brother to be twice his younger brother, younger brothers age should be 15 years. Therefore 15-6=9

MathManiac: yeah wait

ashmita14: oks

MathManiac: kashyap is 21 thus kinshuk is 6 years...now difference is 15...let after x years kashyap becomes twice the age of kinshuk..therefore 2*(6+x)=21+x solving we get x=9

MathManiac: did you understand?

ashmita14: yes thsnk you

ashmita14: thanks

MathManiac: which class are u in?

ashmita14: class six

MathManiac: ok all the best

ashmita14: thanks

Answered by Anonymous

$Answer \: \: \\ \\ Age \: of \: \: kashyap \: \: is \: \: 21 \: years \\ \\ Age \: of \: kinshuk \: = Age \: \: of \: kashyap \: - \: 15 \: years \\ \\ \: therefore \: Age \: of \: kinshuk \: = 21 \: - \: 15 \: = 6 \: years \\ \\ let \: after \: \: x \: years \: Age \: of \: kayshyap \: will \\ be \: 2 \: the \: age \: of \: kinshuk \\ \\ 2(x + 6) = (x + 21) \\ \\ 2x + 12 = x + 21 \\ \\ 2x - x = 21 - 12 \\ \\ x = 9 \\ \\ so \: after \: 9 \: years \: kashyap \: will \: be \: twice \\ as \: old \: as \: kinshuk. \\ \\ Note \: \: \: \\ \\ Age \: of \: kashyap \: after \: x \: years \: will \: be \: \\ (x + 21) \\ and \\ Age \: of \: kinshuk \: after \: x \: years \: will \: be \: \\ (x + 6)$