Question

(3 ki power minus 1 multiply 7 ki power minus 1 ) divide 2 ki power minus 2

Answer 1

Given:

$\dfrac{(3^{-1} \times 7^{-1})}{2^{-2}}$

We have to find, the value of $\dfrac{(3^{-1} \times 7^{-1})}{2^{-2}}$ is equal to:

Solution:

∴ $\dfrac{(3^{-1} \times 7^{-1})}{2^{-2}}$

Using the exponential identity:

$(a^{-1} \times b^{-1})$ = $(ab)^{-1}$

= $\dfrac{(3\times 7)^{-1}}{2^{-2}}$

Using the exponential identity:

$a^{-n} =\dfrac{1}{a^{n} }$

= $\dfrac{2^{2}}{(3\times 7)^{1}}$

= $\dfrac{2^{2}}{(21)^{1}}$

= $\dfrac{4}{21}$

∴ $\dfrac{(3^{-1} \times 7^{-1})}{2^{-2}}$ = $\dfrac{4}{21}$

Thus, the value of $\dfrac{(3^{-1} \times 7^{-1})}{2^{-2}}$ is equal to" $\dfrac{4}{21}$".

Answer 2

Answer:

-1. -1. -2

(3. X. 7. ) Divide. -1/2

Step-by-step explanation:

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