3 ladies and 3 gents can be seated at a round table so that any two and only two of the ladies sit together
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2 Ladies sitting together can be selected in ³P₂ = 6 Ways
now remaining 1 Lady can not sit adjacent to these ladies
so out of remaining 4 seats she can sit only on two seats
hence ²P₁ = 2 Ways
so Ladies can sit in 6 * 2 = 12 Ways
for Three Gents 3 Seats are Left so gents can sit in ³P₃ = 6 Ways
Total Number of Ways = 12 * 6 = 72
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0
not sure about the method
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