Question

3. Leema is watering plants in the school garden using a pipe with a cross-sectional area, A. The force of water from the pipe is F. If there is change in the pressure of water that is 1.5 times the initial pressure, to get this change, what will be the change in the cross-sectional area of the pipe? ?​

Answer 1

Answer:

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Answer 2

Given:-

cross section area = A

force = F

to find change in area so pressure changer to 1.5 times

as we know,

p= \frac{f}{a}p=af

and

a = \frac{f}{p} - - (1)a=pf−−(1)

and

as force is constant so,

a1 = \frac{f}{1.5p}a1=1.5pf

a1 = \frac{1}{1.5} \times \frac{f}{p}a1=1.51×pf

from equ. 1 we got,

a1 = \frac{a}{1.5}a1=1.5a

so,

the change in area is 1.5 time less than normal area.

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