3)Let A= {1,2,3,4), let R be the equivalence relation on AXA defined by (a, b) R
(c,d) if a +d = b +c. Find the equivalence class [(1,3)]
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Answer:
A={1,2,3...9}
R in A×A
(a,b) R (c,d) if (a,b)(c,d) ∈ A∈A
a+b=b+c
Consider (a,b) R (a,b) (a,b)∈A×A
a+b=b+a
Hence, R is reflexive.
Consider (a,b) R (c,d) given by (a,b) (c,d) ∈ A×A
a+d=b+c=>c+b=d+a
⇒(c,d)R(a,b)
Hence R is symmetric.
Let (a,b) R (c,d) and (c,d) R (e,f)
(a,b),(c,d),(e,f),∈A×A
a+b=b+c and c+f=d+e
a+b=b+c
⇒a−c=b−d-- (1)
c+f=d+e-- (2)
Adding (1) and (2)
a−c+c+f=b−d+d+e
a+f=b+e
(a,b)R(e,f)
R is transitive.
R is an equivalence relation.
We select from set A={1,2,3,....9}
a and b such that 2+b=5+a
so b=a+3
Consider (1,4)
(2,5) R (1,4)⇒2+4=5+1
[(2,5)=(1,4)(2,5),(3,6),(4,7),(5,8),(6,9)] is the equivalent class under relation R.
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