3. Let f = {(1, 1) (2, 3)(0,-1) be function
from 2 to z defined by f(x)= as+b
for integers a & b. Determine a&b.
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Answer:
f={(1,1),(2,3),(0,−1),(−1,−3)}
f(x)=ax+b
(1,1)∈f
⇒f(1)=1
⇒a×1+b=1
⇒a+b=1 .....(1)
(0,−1)∈f
⇒f(0)=−1
⇒a×0+b=−1
⇒b=−1
On substituting b=−1 in eqn (1), we get
a+(−1)=1
⇒a=1+1=2
Thus the respective values of a and b are 2 and −1
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