Math, asked by itsthekunal, 10 months ago

3 lights are switched on at an interval of 54,48 and 36 sec resp. EACH light IS KEPT ON for 3 seconds after which it is switched off. The lights are switched on simultaneously at 5:00 a.m. How many times will they be switched on together b/w 6-7 a.m?

Answers

Answered by amitnrw
0

8 times  lights will be switched on together b/w 6-7 a.m

Step-by-step explanation:

3 lights are switched on at an interval of 54,48 and 36 sec respectively

54 = 2 * 3 * 3 * 3

48 = 2 * 2 * 2 * 2 * 3

36 = 2 * 2 * 3 * 3

LCM  = 2 * 2 * 2 * 2 * 3 * 3 * 3  = 432  secs

The lights are switched on simultaneously at 5:00 a.m.

3,888 - 3600 = 288 sec = 4 min 48 secs

=> Lights will switch on at 6:04:48

Light will last switch on together at  6 : 55 : 12

8 times  lights will be switched on together b/w 6-7 a.m

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