А: 3. line PO V line XY, line AB is a transversal. If angle AMQ = 58 find angle PMN, angle XNB, angle XNM, angle PMA, 58 P Q 3 Х N B
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1
Answer:
126
o
In the given figure,
∠POY=90
∘
∠POX+∠POY=180
∘
( Linear pair )
∠POX+90
∘
=180
∘
⇒∠POX=90
∘
a:b=2:3
Let a=2x
∘
and b=3x
∘
∠POX=a+b=5x
90
∘
=5x
⇒x=18
∘
∠MOX=b=3x=54
∘
∠MOX+∠NOX=180
∘
( Linear pair)
b+c=180
∘
54
∘
+c=180
∘
c=180
∘
−54
∘
=126
∘
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