Question

3 litre aqueous solution is prepared by dissolving 4.9 gm H2SO4 in water’ calculate the pH.
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Answer 1

Answer:

1.495

Explanation:

no.of mol = 4.9g/98g/mol = 0.05

molarity of solution = n/V = 0.05/3= 0.016M

[H2SO4] = 0.016M

[H+] =2×0.016M = 0.032M

PH = - log (0.032) = -log(3.2×10^-2)

= 1.495