Question

3 log 2 + 4 log 3 - 2 log 6 = log x then find the value of x.​

Answer 1

Answer:

7

Step-by-step explanation:

i think it is the correct answer

Answer 2

The value of x in the equation $3 log 2 + 4 log 3 - 2 log 6 = log x$ is 8.

Given,

The equation: $3 log 2 + 4 log 3 - 2 log 6 = log x$.

To Find,

The value of x in the equation.

Solution,

The method of finding the value of unknown variable x is as follows -

We have to simplify the equation.

$3 log 2 + 4 log 3 - 2 log 6 = log x$

⇒  $log2^3++log3^4-log6^2=logx$ [Since $mloga=loga^m$]

⇒  $log8+log81-log36=logx$

⇒  $log(\frac{8*81}{36} )=logx$ [Since $log+logb=log ab$ and $loga - logb=log(\frac{a}{b} )$]

⇒  $log18=logx$

⇒  $x=18$. [Cancelling logarithm function on both sides]

Hence, the value of x in the equation $3 log 2 + 4 log 3 - 2 log 6 = log x$ is 8.

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