3√log x + 2log √X^-1 = 2
Answers
Given : 3√log x + 2log √x⁻¹ = 2
To Find : Value of x
Solution:
3√log x + 2log √x⁻¹ = 2
=> 3√log x + 2log √(1/x) = 2
=> 3√log x + 2log (1/√x) = 2
=> 3√log x - 2log (√x) = 2
=> 3√log x - 2log (√x) = 2
=> 3√log x - log (√x)² = 2
=> 3√log x - log (x) = 2
=> log (x) - 3√log x + 2 = 0
=> log (x) - 2√log x - √log x + 2 = 0
=> √log x ( √log x - 2) - 1 ( √log x - 2 ) = 0
=> (√log x - 1)( √log x - 2 ) = 0
√log x - 1 = 0
=> √log x = 1
=> log x = 1
=> x = 10
√log x - 2 =0
=> √log x = 2
=> log x = 4
=> x = 10000
x = 10 & 10000
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