Question

3(log5-log3) - (log5- 2log6)=2-logn find n

Answer 1

=3log5-3log3-log5+2log3+2log2=2-logn

=2log5-log3+2log2=2log5+2log2-logn

=-log3=-logn

= n=3

Answer 2

Given $3(\log 5 - \log 3)-(\log 5 - 2 \log 6)=2-\log n$. This equation can be written as

$3\log (\frac{5}{3} )-(\log 5 - \log (36))=2-\log n \\ \log (\frac{125}{27} )-\log (\frac{5}{36})=2-\log n \\ \log (\frac{125}{27}\frac{36}{5} )=\log (\frac{100}{n}) \\ \log (\frac{900}{27})=\log (\frac{100}{n}) \\ \frac{100}{n}=\frac{900}{27}\\ n=3$