Question

3. logba x logcb can be written as

A) logac B) logca C) logab D) logibc
​

Answer 1

Answer:

B

Step-by-step explanation:

*i think b is the best answer may be *

Answer 2

$log_{a}(b)\times log_{b}(c)=log_{a}(c)$

Option B) $log_{a}(c)$

Tips:

We know that,

$log_{a}(b)=\dfrac{log_{e}(a)}{log_{e}(b)}$

[In place of 'e', we can take Natural number.]

Step-by-step explanation:

Now, $log_{a}(b)\times log_{b}(c)$

• Hint: Here, we take 'e' as the new base.

$=\dfrac{log_{e}(b)}{log_{e}(a)}\times \dfrac{log_{e}(c)}{log_{e}(b)}$

$=\dfrac{log_{e}(c)}{log_{e}(a)}$

$=log_{a}(c)$

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