Question

3. loge X + log(1+x) = 0 is equivalent to
(a) x2+x+e = 0
(b) x2+x-e = 0
(c) x2+x+1 = 0
(d) x2+x-1 = 0​

Answer 1

Step-by-step explanation:

x2+x+e=0

Thank you