Math, asked by coronavirus45, 8 months ago

3√logx + 2log√x^-1 = 2
can anyone plz.... solve this :¡

Answers

Answered by saghnikchatterjee

1

Answer:

3logx^1/2 +2 log x ^-1/2

3/2log x -log x

1/2log x =2

log x =4

e^4=x

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